수학동아 - 폴리매스

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[잡담] 문제가 뭘까요(C언어)

켋 2020.03.06 21:48 조회 488

페이스북 트위터 카카오톡 카카오스토리 네이버블로그 네이버밴드

//네자리수의 반복 abcdabcd 여덟자리수가 어떤 수로 나누어떨어질때, abcdabcd
#include 
int main()
{
    unsigned int a, b, c, d;

    for (a = 1; a < 9; a++) {
        for (b = 0; b < 9; b++) {
            for (c = 0; c < 9; c++) {
                for (d = 0; d < 9; d++) {
                    if ((10001000*a+1000100*b+100010*c+10001*d)% 22879 == 0 ) {
                        printf("%d\n", 10001000*a+1000100*b+100010*c+10001*d);
                    }
                }
            }
        }
    }

    return 0;
}

abcdabcd꼴의 8자리 수중 22879로 나누어떨어지는 수를 찾는 문제(함풀문 풀려고 만듦)를 풀려고 만든 코드인데

저 코드를 실행시켜보면 88518851까지 출력되는데, 90189018도 22879에 의해 나누어떨어집니다.

뭐가 문제일까요

이전글 음... 요약을 해보자면...

다음글 매스펀 기네스북

추천 0 목록보기

댓글 작성하기

21세기오일러 Lv.11 2020.03.06 21:54

저는 파이썬으로 밖에 ㅠㅠ

댓글 작성하기 좋아요0 댓글수0
지구 Lv.6 2020.03.06 21:56

c언어 님은 회원 이름입니다.

댓글 작성하기 좋아요0 댓글수2
- 21세기오일러 Lv.11 2020.03.06 22:01
  
  아 그 분 멘토링도 받으셨는데
  
  좋아요0
- 켋 Lv.7 2020.03.06 22:05
  
  띠용;;
  
  좋아요0
개발하는몰랑 Lv.15 2020.03.06 22:24

기본 알고리즘만 간단히 남겨봅니다ㅎㅎ

var div_num = 22879;

for(var i=1000, limit=9999; i<=limit; i++){
   if(i*10001 % div_num == 0){
       // i * 10001 출력;
   }
}

댓글 작성하기 좋아요0 댓글수2
- 개발하는몰랑 Lv.15 2020.03.06 22:29
  
  본문의 코드에서는 조건식이 9보다 작게로 되어 있네요. 작거나 같게로~
  
  좋아요0
- 켋 Lv.7 2020.03.07 00:29
  
  아..감사합니다 ㅎㅎ
  
  좋아요0

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