이 정리가 중2 과정이라 엇각, 동위각 이런거만 활용해서 증명방법을 알려주더라고요.
어쩌다 중1에 나오는 합동으로 새로운 방법을 알아낸 것 같은데 수학잘하시는 분들 확인 부탁드립니닷.
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그런데 저 중간에 내각의 이등분선정리가 포함돼 있는데 거기서 중2 과정이 나오지 않나요? (아닌가?)
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Line: 202
Function: mkdirFile: /volume1/web/PhpstormProjects/www_polymath_co_kr/application/libraries/Common.php
Line: 236
Function: getLatexImgFile: /volume1/web/PhpstormProjects/www_polymath_co_kr/application/views/ver3/inc/view_comment_list.php
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Function: viewFile: /volume1/web/PhpstormProjects/www_polymath_co_kr/application/controllers/ver3/Contents.php
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Function: require_once조금 늦게 이 글을 봤네요! 이 조건에서는 합동으로 충분히 이 외각 이등분선 정리도 증명할 수 있어요! 저로서는 왠만한 도형 공식, 정리의 증명의 열쇠가 삼각형의 닮음, 합동에 있다고 보거든요~ 마지막줄의 '
에서'를 추가하고 'AE:BE = AC:BC'라고 오타를 정정하시면 증명 과정을 더 쉽게 이해할 수 있을 것 같아요! 외각의 이등분선과 선분 BC=DC가 같다는 두 조건에 의하여 합동임을 보이고, 그 합동에서 같은 요소와 내각의 이등분선을 알아내었으니 
의 외각의 이등분선 정리가 성립함을 보일 수가 있어요!
